2b^2+5b-8/b^2+b+5/b+2=-3/b

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Solution for 2b^2+5b-8/b^2+b+5/b+2=-3/b equation: 



2b^2+5b-8/b^2+b+5/b+2=-3/b

We move all terms to the left:

2b^2+5b-8/b^2+b+5/b+2-(-3/b)=0



Domain of the equation: b^2!=0

b^2!=0/

b^2!=√0

b!=0

b∈R





Domain of the equation: b!=0

b∈R





Domain of the equation: b)!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

2b^2+6b-8/b^2+5/b-(-3/b)+2=0

We get rid of parentheses

2b^2+6b-8/b^2+5/b+3/b+2=0

We calculate fractions

We do not support ebpression: b^3

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